4d^(2/3)+5d^(1/3)-6

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Solution for 4d^(2/3)+5d^(1/3)-6 equation:


d in (-oo:+oo)

4*d^(2/3)+5*d^(1/3)-6 = 0

t_1 = d^(1/3)

4*t_1^2+5*t_1^1-6 = 0

4*t_1^2+5*t_1-6 = 0

DELTA = 5^2-(-6*4*4)

DELTA = 121

DELTA > 0

t_1 = (121^(1/2)-5)/(2*4) or t_1 = (-121^(1/2)-5)/(2*4)

t_1 = 3/4 or t_1 = -2

t_1 = -2

d^(1/3)+2 = 0

1*d^(1/3) = -2 // : 1

d^(1/3) = -2

( -2 < 0 i 1/3 in (0:1) ) => d naleu017Cy do O

t_1 = 3/4

d^(1/3)-3/4 = 0

1*d^(1/3) = 3/4 // : 1

d^(1/3) = 3/4

d^(1/3) = 3/4 // ^ 3

d = 27/64

d = 27/64

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